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28 Jul 2023
@danielp3344:matrix.orgDaniel

V = IR (voltage = current * resistance)

Rearrange that to get I = V/R, so current is determined by the resistance (something inherent to the circuit) and voltage

10:33:45
@danielp3344:matrix.orgDanielSo the current that a given circuit/component will draw will not change if the voltage does not change (assuming no other changes)10:35:00
@danielp3344:matrix.orgDanielIf it helps to use the water analogy, the anount of flow (current) through a pipe is determined only by the size of the pipe (resistance) and pressure (voltage), not by the maximum flow the supply can supply (unless the resistance is too low)10:37:19
* @danielp3344:matrix.orgDaniel was asleep about 5 minutes ago, hopefully this is somewhat articulate/useful10:38:20
@rd2:matrix.orgrd2In other words, the current coming from the battery will step down according to the resistance of the logic board. This resistance determines the maximum allowed current of 14.7A, regardless of the battery's capacity to provide a continuous current of 30A. Have I understood this correctly?12:27:50
@danielp3344:matrix.orgDanielThis is not universally true, but as a rule, if voltage is constant current will be too12:38:23
@danielp3344:matrix.orgDaniel* The above is not universally true, but as a rule, if voltage is constant current will be too12:38:52
@rd2:matrix.orgrd2I have to check the voltage range the bms allows in this batter13:00:01
@rd2:matrix.orgrd2image.png
Download image.png
13:04:57
@rd2:matrix.orgrd2the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so the P= IR = 12.6V*14.7A=185.22W I calculate the resistance from above R=V/I 12.6/14.7= 0.857142857 Ohm The allowed voltage range in the battery 14V>=V<=14.2V Calculate the Currents range for the above voltage I1=V/R = 14/0.857142857=16.33A I2=14.2/ 0.857142857=16.56A 13:16:21
@rd2:matrix.orgrd2 * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so the P= IR = 12.6V*14.7A=185.22W
I calculate the resistance from above R=V/I 12.6/14.7= 0.857142857 Ohm The allowed voltage range in the battery 14V>=V<=14.2V
Calculate the Currents range for the above voltage I1=V/R = 14/0.857142857=16.33A I2=14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A
13:18:44
@rd2:matrix.orgrd2 * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so the P= IR = 12.6V*14.7A=185.22W I calculate the resistance from above R=V/I 12.6/14.7= 0.857142857 Ohm The allowed voltage range in the battery 14V>=V<=14.2V Calculate the Currents range for the above voltage I=V/R I1= 14/0.857142857=16.33A I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A 13:20:38
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm
The allowed voltage range in the battery 14V>=V<=14.2V

Calculate the Currents range for the above voltage I=V/R
I1= 14/0.857142857=16.33A

I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:22:02
@rd2:matrix.orgrd2Redacted or Malformed Event13:23:17
@rd2:matrix.orgrd2
In reply to @danielp3344:matrix.org
The above is not universally true, but as a rule, if voltage is constant current will be too
The logic board component resistance is unable to handle the increase in current. correct?
13:24:28
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm
The allowed voltage range in the battery 14V-14.2V

Calculate the Currents range for the above voltage I=V/R
I1= 14/0.857142857=16.33A

I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:28:45
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm
The allowed voltage range in the battery 14V-14.2V

The Currents range of the above voltage I=V/R
I1= 14/0.857142857=16.33A

I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:29:25
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm
The allowed voltage range in the battery 14V-14.2V

The Currents range of the battery voltage range =16.33A-16.56A
I=V/R
I1= 14/0.857142857=16.33A

I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:31:03
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm
The allowed voltage range in the battery 14V-14.2V

The Currents range of the battery voltage range =16.33A-16.56A

I=V/R
I1= 14/0.857142857=16.33A
I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:32:05
@danielp3344:matrix.orgDanielAny semiconductor (your entire board) is inherently non ohmic13:32:28
@danielp3344:matrix.orgDanielSo behavior at a different voltage is unpredictable13:32:46
@rd2:matrix.orgrd2 *

the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so P= I*R
12.6V*14.7A=185.22W

I calculate the resistance from above R=V/I
12.6/14.7= 0.857142857 Ohm

given Battery's allowed voltage range = 14V-14.2V

Calculate the current range from the voltage range =16.33A-16.56A

I=V/R
I1= 14/0.857142857=16.33A
I2= 14.2/ 0.857142857=16.56A

raise in current is 1.63A-1.86A

13:34:02
@rd2:matrix.orgrd2
In reply to @danielp3344:matrix.org
So behavior at a different voltage is unpredictable
if we assume that the actual resistance is 0.857142857 Ohm. does that mean this battery can fry the board?
13:36:14
@danielp3344:matrix.orgDanielSemiconductors don't have a "resistance" per se13:36:38
@danielp3344:matrix.orgDanielBut yes they will tend to draw more current with increased voltage, which can certainly damage things13:37:11
@danielp3344:matrix.orgDanielJust use a buck regulator tho13:37:32
@danielp3344:matrix.orgDanielhttps://www.ebay.com/itm/124976393245?hash=item1d192c6c1d:g:0LoAAOSwiRdhejzl&amdata=enc%3AAQAIAAAA8HSsPabBxrZDNEicjix5QaeydgsQ1Zv0TXMBSKhlOVMXl951CLKDkomrQWsvUWta8DiELV1sWuH2x%2BgfSLz0oIWpDzDtJny2U4UCYAV3p4Wl2vI6ycYYaF0TsaxirCmzMvEV2ghMkNJdOfl7S1vQmkgH7AFqEyh3Kw%2Fn1ttVw9FO8L0co8Yw0tzZeJ0cdyBLZgjo%2BoXH2QEeU6XrrN7WY8k4udk%2FIb1YFuAAv%2B5fcuxtCIAouN9tjNabpLNjL2QVZywrLsHuu4F47oBvx4cSnqEpVKhboJT6GBm3l4Joe9Wa4BDzwyrA6c38oNPpdCSmwA%3D%3D%7Ctkp%3ABk9SR7Kaw8uzYg13:38:30
@rd2:matrix.orgrd2I am trying to get a battery bms that suits the logic board to evade having to install a buck converter13:38:33
@danielp3344:matrix.orgDaniel* https://www.ebay.com/itm/12497639324513:39:01
@rd2:matrix.orgrd2there is a dude who is running his m1 mac mini on a v mount battery rated 99W 13:39:31

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