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| Sender | Message | Time |
|---|---|---|
| 28 Jul 2023 | ||
 rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so the P= IR = 12.6V*14.7A=185.22W I calculate the resistance from above R=V/I 12.6/14.7= 0.857142857 Ohm The allowed voltage range in the battery 14V>=V<=14.2V Calculate the Currents range for the above voltage I1=V/R = 14/0.857142857=16.33A I2=14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:18:44 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so the P= IR = 12.6V*14.7A=185.22W I calculate the resistance from above R=V/I 12.6/14.7= 0.857142857 Ohm The allowed voltage range in the battery 14V>=V<=14.2V Calculate the Currents range for the above voltage I=V/R I1= 14/0.857142857=16.33A I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:20:38 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above Calculate the Currents range for the above voltage I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:22:02 |
| rd2 | Redacted or Malformed Event | 13:23:17 |
| rd2 | In reply to @danielp3344:matrix.orgThe logic board component resistance is unable to handle the increase in current. correct? | 13:24:28 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above Calculate the Currents range for the above voltage I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:28:45 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above The Currents range of the above voltage I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:29:25 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above The Currents range of the battery voltage range =16.33A-16.56A I2= 14.2/ 0.857142857=16.56A raise in current is 1.63A-1.86A | 13:31:03 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above The Currents range of the battery voltage range =16.33A-16.56A
raise in current is 1.63A-1.86A | 13:32:05 |
 Daniel Peterson | Any semiconductor (your entire board) is inherently non ohmic | 13:32:28 |
| Daniel Peterson | So behavior at a different voltage is unpredictable | 13:32:46 |
| rd2 | * the maximum power consumption of the logic board states maximum continuous watt consumption 185W and the maximum allowed current is 14.7A so I calculate the resistance from above given Battery's allowed voltage range = 14V-14.2V Calculate the current range from the voltage range =16.33A-16.56A
raise in current is 1.63A-1.86A | 13:34:02 |
| rd2 | In reply to @danielp3344:matrix.orgif we assume that the actual resistance is 0.857142857 Ohm. does that mean this battery can fry the board? | 13:36:14 |
| Daniel Peterson | Semiconductors don't have a "resistance" per se | 13:36:38 |
| Daniel Peterson | But yes they will tend to draw more current with increased voltage, which can certainly damage things | 13:37:11 |
| Daniel Peterson | Just use a buck regulator tho | 13:37:32 |
| Daniel Peterson | https://www.ebay.com/itm/124976393245?hash=item1d192c6c1d:g:0LoAAOSwiRdhejzl&amdata=enc%3AAQAIAAAA8HSsPabBxrZDNEicjix5QaeydgsQ1Zv0TXMBSKhlOVMXl951CLKDkomrQWsvUWta8DiELV1sWuH2x%2BgfSLz0oIWpDzDtJny2U4UCYAV3p4Wl2vI6ycYYaF0TsaxirCmzMvEV2ghMkNJdOfl7S1vQmkgH7AFqEyh3Kw%2Fn1ttVw9FO8L0co8Yw0tzZeJ0cdyBLZgjo%2BoXH2QEeU6XrrN7WY8k4udk%2FIb1YFuAAv%2B5fcuxtCIAouN9tjNabpLNjL2QVZywrLsHuu4F47oBvx4cSnqEpVKhboJT6GBm3l4Joe9Wa4BDzwyrA6c38oNPpdCSmwA%3D%3D%7Ctkp%3ABk9SR7Kaw8uzYg | 13:38:30 |
| rd2 | I am trying to get a battery bms that suits the logic board to evade having to install a buck converter | 13:38:33 |
| Daniel Peterson | * https://www.ebay.com/itm/124976393245 | 13:39:01 |
| rd2 | there is a dude who is running his m1 mac mini on a v mount battery rated 99W | 13:39:31 |
| Daniel Peterson | In reply to @rd2:matrix.orgTypically a bms won't regulate voltage, it only controls charging and maybe has a current limit | 13:39:42 |
| rd2 | I am trying to rely on bmp that has suitable overchange and undercharge protection | 13:40:19 |
| Daniel Peterson | Batteries do not have an inherently stable voltage | 13:40:37 |
| Daniel Peterson | You will need a regulator somewhere | 13:40:48 |
| Daniel Peterson | Unless your circuit can tolerate a voltage swing of a few volts | 13:41:09 |
| rd2 | there are these smart bmses that you can enter values via software so you can control the protection range | 13:41:22 |
| Daniel Peterson | That only controls the max/min voltage of the pack | 13:41:42 |
| Daniel Peterson | Which dramatically reduces capacity | 13:41:52 |
| rd2 | even you can control current | 13:42:07 |
| Daniel Peterson | For example if you run a 3s lipo pack from 12.6-12.0v you're using only 20% of capacity | 13:43:02 |