| 29 Dec 2023 |
 dionisos | In reply to @qwjyh:matrix.org
Do you want to generate a function based on a type automatically? If normal multiple dispatch doesn't meet your need, you should use macro. Yes this is what I want | 00:09:11 |
| dionisos | Oh, I just realized the "where MyType", just make MyType a variable | 00:10:03 |
 qwjyh | Simple example for the syntax:
```
julia> struct MyType
v::Int64
end
julia> function (t::MyType)(a::T, b::T) where {T <: Integer}
a + b + t.v
end
julia> x = MyType(1)
MyType(1)
julia> x(1, 2)
4
``` | 00:10:04 |
| dionisos | In reply to @qwjyh:matrix.org
Simple example for the syntax:
```
julia> struct MyType
v::Int64
end
julia> function (t::MyType)(a::T, b::T) where {T <: Integer}
a + b + t.v
end
julia> x = MyType(1)
MyType(1)
julia> x(1, 2)
4
``` My problem is that the function is in a closure, and it gives me the error :
ERROR: LoadError: syntax: local variable MyType cannot be used in closure declaration
| 00:11:31 |
| dionisos | I am very probably misunderstanding something. | 00:12:22 |
| qwjyh | ```
julia> macro genfunc(t)
quote
function test(a::$t, b::$t)
a.v + b.v
end
end
end
@genfunc (macro with 1 method)
julia> test = @genfunc MyType
#83#test (generic function with 1 method)
julia> test(x, y)
3
``` | 00:14:55 |
| dionisos | I am wondering if I can do it without a macro, I will do it with a macro if there is not another way, but I feel like there is some hole in my understanding and finding how to do it without a macro will help. | 00:18:07 |
| dionisos | In reply to @qwjyh:matrix.org
Simple example for the syntax:
```
julia> struct MyType
v::Int64
end
julia> function (t::MyType)(a::T, b::T) where {T <: Integer}
a + b + t.v
end
julia> x = MyType(1)
MyType(1)
julia> x(1, 2)
4
``` I realize I misunderstood you question, but at least now I understand the syntax you where using, thank you. | 00:25:22 |
| dionisos | Ok after some testes and research, it seems like I should use a macro for this. | 00:27:20 |
| dionisos | Thank you for you help qwjyh | 00:27:34 |
| dionisos | In reply to @qwjyh:matrix.org
Simple example for the syntax:
```
julia> struct MyType
v::Int64
end
julia> function (t::MyType)(a::T, b::T) where {T <: Integer}
a + b + t.v
end
julia> x = MyType(1)
MyType(1)
julia> x(1, 2)
4
``` * I realize I misunderstood your question, but at least now I understand the syntax you where using, thank you. | 00:27:44 |
| 30 Dec 2023 |
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| 3 Jan 2024 |
 @malte:maltee.de | Can I interpolate a heatmap while plotting? I have a function that takes two values as input and produces a third one as an output. I want to display the output on the x axis and the two inputs on the y and z axis. Typically, heatmaps are laid out on a grid, but I can't produce a grid because I cannot reverse my functions. | 09:11:29 |
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