| 28 Mar 2024 |
 jjj333_p (any pronouns) | i think i was confused by the question | 15:07:43 |
 knoppix | the question is to check if the set of vectors is linearly dependent or not | 15:08:06 |
| jjj333_p (any pronouns) | i think its because 4v1 + 2v2 = v3 which i thought meant independent since there was an answer but that actually wouldnt makee sense | 15:08:43 |
| knoppix | independent is when the only possibility to obtain zero is:
0 v1 + 0 v2 + 0 v3 = 0 | 15:09:22 |
| knoppix | with other words, if any of the vectors can be result of the others | 15:09:54 |
| knoppix | then its independent | 15:10:02 |
| jjj333_p (any pronouns) | oh so its the exact opposite | 15:10:05 |
| jjj333_p (any pronouns) | i think i missed that part of the lecture | 15:10:14 |
 beepboopbeepboop1234 | Any three vectors in a 2D space are going to be linear dependent | 15:10:58 |
| beepboopbeepboop1234 | Doesn't matter what the numbers are | 15:11:32 |
| jjj333_p (any pronouns) | that makes a lot of sense | 15:11:50 |
| beepboopbeepboop1234 | Two vectors in 2D space can be independent depending on the numbers | 15:11:57 |
| beepboopbeepboop1234 | but three or more cannot | 15:12:05 |
| beepboopbeepboop1234 | This also applies to other dimensions | 15:13:38 |
| beepboopbeepboop1234 | So four vectors in a 3D space will be linear dependent | 15:13:58 |
| jjj333_p (any pronouns) | pidgeonhole principle and all yea | 15:22:18 |
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| 6 Apr 2024 |
| jjj333_p (any pronouns) changed their display name from jjj333_p (any pronouns) to Dendrite figure yourself the fuck out. | 01:09:37 |
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